Question:
If a triangle and a parallelogram are on the same base and between the same parallels, then the ratio of the area of the triangle to the area of the parallelogram is
(a) 1 : 2
(b) 1 : 3
(c) 1 : 4
(d) 3 : 4
Figure
Solution:
(a) 1:2
If a triangle and a parallelogram are on the same base and between the same parallels, then the area of the triangles is half the area of the parallelogram.
i.e., area of triangle $=\frac{1}{2} \times$ area of parallelogram
$\therefore$ Required ratio = area of triangle : area of parallelogram $=\frac{1}{2}: 1=1: 2$