If a hyperbola has length of its conjugate axis equal to 5 and the distance between its foci is 13 ,
Question:
If a hyperbola has length of its conjugate axis equal to 5 and the distance between its foci is 13 , then the eccentricity of the hyperbola is :-
Correct Option: , 4
Solution:
$2 \mathrm{~b}=5$ and $2 \mathrm{ae}=13$
$b^{2}=a^{2}\left(e^{2}-1\right) \Rightarrow \frac{25}{4}=\frac{169}{4}-a^{2}$
$\Rightarrow \mathrm{a}=6 \Rightarrow \mathrm{e}=\frac{13}{12}$