If a current of 0.5 ampere flows through a metallic wire for 2 hours,

I = 0.5 A

t = 2 hours = 2 × 60 × 60 s = 7200 s

Thus, Q = It

= 0.5 A × 7200 s

= 3600 C

We know that  number of electrons.

Then,

Then,

Hence, number of electrons will flow through the wire.