Question:
If $A \subset B$, prove that $B^{\prime} \subset A^{\prime} .$
Solution:
As $A \subset B$ the set $A$ is inside set $B$
Hence $A \cup B=B$
Taking compliment
$\Rightarrow(A \cup B)^{\prime}=B .^{\prime}$
Using de-morgans law $(A \cup B)^{\prime}=A^{\prime} \cap B .^{\prime}$
$\Rightarrow A^{\prime} \cap B^{\prime}=B .^{\prime}$
$A^{\prime} \cap B^{\prime}=B^{\prime}$ means that the set $B^{\prime}$ is inside the set $A . .^{\prime}$
Representing in Venn diagram,
As seen from Venn diagram $B^{\prime} \subset A . '$
Hence proved