Question:
If $A$ and $B$ are invertible matrices of the same order then $(A B)^{-1}=?$
A. $\left(A^{-1} \times B^{-1}\right)$
B. $\left(A \times B^{-1}\right)$
C. $\left(A^{-1} \times B\right)$
D. $\left(B^{-1} \times A^{-1}\right)$
Solution:
$(A B)(A B)^{-1}=1$
