Question:
If 486*7 is divisible by 9, then the least value of * is
(a) 0
(b) 1
(c) 3
(d) 2
Solution:
(d) 2
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
$4+8+6+^{*}+7=25+^{*}$
Now, $25+^{*}=27 \quad$ (if $^{*}=2$ and 27 is divisible by 9 )