Question:
If 1176=2a3b7c, find a, b and c.
Solution:
First find out the prime factorisation of 1176.
It can be observed that 1176 can be written as $2^{3} \times 3^{1} \times 7^{2}$.
$1176=2^{3} 3^{1} 7^{2}=2^{a} 3^{b} 7^{c}$
Hence, $a=3, b=1$ and $c=2$.