Question: If 10 different balls are to be placed in 4 distinct boxes at random, then the probability that two of these boxes contain exactly 2 and 3 balls is :
$\frac{945}{2^{11}}$
$\frac{965}{2^{11}}$
$\frac{945}{2^{10}}$
$\frac{965}{2^{10}}$
Correct Option: , 3
Solution:
