(i) In the explanation of the photoelectric effect, we assume one photon of frequency ν collides with an electron and transfers its energy. This leads to the
equation for the maximum energy Emax of the emitted electron as Emax = hν – φ0 where φ0 is the work function of the metal. If an electron absorbs 2 photons
(each of frequency ν ) what will be the maximum energy for the emitted electron?
(ii) Why is this fact (two-photon absorption) not taken into consideration in our discussion of the stopping potential?
(i) From the question, the energy absorbed by the electron is two protons with frequency v and v’= 2v where v’ is the frequency from the emitted electron.
Emax = hv – ϕ0
(ii) The emission is negligible as the chances of the same proton absorbing the energy is very low.