Question: Hydrogen peroxide reacts with iodine in basic medium to give:
$\mathrm{IO}_{4}^{-}$
$\mathrm{IO}^{-}$
$\mathrm{I}^{-}$
$\mathrm{IO}_{3}^{-}$
Correct Option: , 3
Solution:
$\mathrm{I}_{2}+\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{OH} \longrightarrow 2 \mathrm{I}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$
