How much electricity is required in coulomb for the oxidation of

(i) According to the question,

$\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}_{2}+\frac{1}{2} \mathrm{O}_{2}$

Now, we can write:

$\mathrm{O}^{2-} \longrightarrow \frac{1}{2} \mathrm{O}_{2}+2 \mathrm{e}^{-}$

Electricity required for the oxidation of 1 mol of H2O to O2 = 2 F

= 2 × 96487 C

= 192974 C

(ii) According to the question,

$\mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-1}$

Electricity required for the oxidation of 1 mol of FeO to Fe2O3 = 1 F

= 96487 C