Question:
How much clay is dug out in digging a well measuring 3 m by 2 m by 5 m?
Solution:
The measure of well is $3 \mathrm{~m} \times 2 \mathrm{~m} \times 5 \mathrm{~m}$.
$\therefore$ Volume of the clay dug out $=(3 \times 2 \times 5) \mathrm{m}^{3}=30 \mathrm{~m}^{3}$