Question:
How many terms of the AP 26, 21 16, 11, …. are needed to give the sum 11?
Solution:
To Find: Number of terms required
Let the number of terms be n.
$S_{n}=\frac{n}{2}[2 a+(n-1) d]$
$\Rightarrow \frac{n}{2}[52+(n-1)(-5)]=11 \Rightarrow \mathrm{n}[52-5 n+5]=22$
$\Rightarrow n(57-5 n)=11 \times 2=11[57-5(11)]$
$\Rightarrow \mathrm{n}=11$
11 terms are required to give the sum 11 .