Question:
How many terms are there in the AP $11,18,25,32,39, \ldots .207 ?$
Solution:
To Find: we need to find a number of terms in the given AP.
Given: The series is $11,18,25,32,39, \ldots 207$
$a_{1}=11, a_{2}=18, d=18-11=7$ and $a_{n}=207$
(Where $a=a_{1}$ is first term, $a_{2}$ is second term, $a_{n}$ is nth term and $d$ is common difference of given $\mathrm{AP}$ )
Formula Used: $a_{n}=a+(n-1) d$
$a_{n}=207=a_{1}+(n-1)(7)$
$207-11=(n-1)(7)$ [subtract 11 on both sides]
$196=(n-1)(7)$
$28=(n-1)$ [Divide both side by 7 ]
$\mathrm{n}=29$ [add 1 on both sides]
So there are 29 terms in this AP.