Question:
How many persons can be accommodated in a hall of length 16 m. breadth 12.5 m and height 4.5 m, assuming that 3.6 m3 of air is required for each person?
Solution:
Total volume of the hall $=(16 \times 12.5 \times 4.5)=900 m^{3}$
It is given that $3.6 \mathrm{~m}^{3}$ of air is required for each person.
The total number of persons that can be accommodated in that hall $=\frac{\text { Total volume }}{\mathrm{Volume} \text { required by each person }}=\frac{900}{3.6}$
$=250$ people