Question:
How many persons can be accommodated in a dining hall of dimensions (20 m × 16 m × 4.5 m), assuming that each person requires 5 cubic metres of air?
Solution:
Volume of the dining hall $=(20 \times 16 \times 4.5) \mathrm{m}^{3}$
$=1440 \mathrm{~m}^{3}$
Volume of air required by each person $=5 \mathrm{~m}^{3}$
$\therefore$ Capacity of the dining hall $=\frac{\text { volume of dining hall }}{\text { volume of air required by each person }}=\frac{1440}{5}=288$ persons