Question:
How many numbers lie between 10 and 300, which divided by 4 leave a remainder 3?
Solution:
Here, the first number is 11, which divided by 4 leave remainder 3 between 10 and 300. Last term before 300 is 299, which divided by 4 leave
remainder 3.
∴ 11,15,19,23…. 299
Here, first term (a) = 11, common difference d = 15 -11 = 4
$\because \quad$ nth term, $a_{n}=a+(n-1) d=l \quad$ [last term]
$\Rightarrow \quad 299=11+(n-1) 4$
$\Rightarrow \quad 4(n-1)=288$
$\Rightarrow \quad(n-1)=72$
$\therefore \quad n=73$