Question.
How many neutrons and protons are there inthe following nuclei?
${ }_{6}^{13} \mathrm{C}$
${ }_{8}^{16} \mathrm{O}$
${ }_{12}^{24} \mathrm{Mg}$
${ }_{26}^{56} \mathrm{Fe}$
${ }_{38}^{88} \mathrm{Sr}$
How many neutrons and protons are there inthe following nuclei?
${ }_{6}^{13} \mathrm{C}$
${ }_{8}^{16} \mathrm{O}$
${ }_{12}^{24} \mathrm{Mg}$
${ }_{26}^{56} \mathrm{Fe}$
${ }_{38}^{88} \mathrm{Sr}$
Solution:
${ }^{13}{ }_{6} \mathrm{C}:$
Atomic mass $=13$
Atomic number $=$ Number of protons $=6$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=13-6=7$
${ }_{8}^{16} \bigcirc$
Atomic mass $=16$
Atomic number $=8$
Number of protons $=8$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=16-8=8$
${ }_{12}^{24} \mathrm{Mg}$ :
Atomic mass $=24$
Atomic number $=$ Number of protons $=12$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=56-26=30$
${ }_{25}^{56} \mathrm{Fe}:$
Atomic mass $=56$
Atomic number $=$ Number of protons $=26$
Number of neutrons = (Atomic mass) - (Atomic number)
$=56-26=30$
${ }_{38}^{88} \mathrm{Sr} \quad:$
Atomic mass $=88$
Atomic number $=$ Number of protons $=38$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=88-38=50$
${ }^{13}{ }_{6} \mathrm{C}:$
Atomic mass $=13$
Atomic number $=$ Number of protons $=6$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=13-6=7$
${ }_{8}^{16} \bigcirc$
Atomic mass $=16$
Atomic number $=8$
Number of protons $=8$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=16-8=8$
${ }_{12}^{24} \mathrm{Mg}$ :
Atomic mass $=24$
Atomic number $=$ Number of protons $=12$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=56-26=30$
${ }_{25}^{56} \mathrm{Fe}:$
Atomic mass $=56$
Atomic number $=$ Number of protons $=26$
Number of neutrons = (Atomic mass) - (Atomic number)
$=56-26=30$
${ }_{38}^{88} \mathrm{Sr} \quad:$
Atomic mass $=88$
Atomic number $=$ Number of protons $=38$
Number of neutrons $=$ (Atomic mass) $-$ (Atomic number)
$=88-38=50$