Question:
How many geometrical isomers are possible in the following coordination entities?
(i) [Cr(C2O4)3]3− (ii) [Co(NH3)3Cl3]
Solution:
(i) For [Cr(C2O4)3]3−, no geometric isomer is possible as it is a bidentate ligand.
(ii) [Co(NH3)3Cl3]
Two geometrical isomers are possible.
