Given below are two statements :
Statement I : $\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{3-},\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ and $\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ are d $^{2} \mathrm{sp}^{3}$ hybridised.
Statement II : $\left[\mathrm{MnCl}_{6}\right]^{3-}$ and $\left[\mathrm{FeF}_{6}\right]^{3-}$ are paramagnetic and have 4 and 5 unpaired electrons, respectively.
In the light of the above statements, choose the correct answer from the options given below :
Correct Option: , 4
$\mathrm{d}^{4}$ configuration, SFL $\mathrm{d}^{5}$ configuration, SFL $\mathrm{d}^{6}$ configuration, Chelating ligand
$\Rightarrow$ All will have larger splitting hence $\mathrm{d}^{2} \mathrm{sp}^{3}$ hybridisation
