Question:
Given below are the statements about diborane
(a) Diborane is prepared by the oxidation of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$
(b) Each boron atom is in $\mathrm{sp}^{2}$ hybridized state
(c) Diborane has one bridged 3 centre-2-electron bond
(d) Diborane is a planar molecule
The option with correct statement(s) is -
Correct Option: , 2
Solution:
Diborane is prepared by the reaction of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$.
$2 \mathrm{NaBH}_{4}+\mathrm{I}_{2} \rightarrow \mathrm{B}_{2} \mathrm{H}_{6}+2 \mathrm{NaI}+\mathrm{H}_{2}$
In diborane, 'B' is $\mathrm{sp}^{3}$ hybrid, it is Non-planar and two $3 c-2 e^{-}$bonds are present.