Question:
For what value of $k,-4$ is a zero of the polynomial $x^{2}-x-(2 k+2) ?$
Solution:
We know that if $x=\alpha$ is zero polynomial then $x-2$ is a factor of $f(x)$
Since $-4$ is zero of $f(x)$
Therefore $x+4$ is a factor of $f(x)$
Now, we divide $f(x)=x^{2}-x-(2 k+2)$ by $g(x)=x+4$ to find the value of $k$
Now, Remainder $=0$
$-2 k+18=0$
$-2 k=-18$
$k=\frac{-18}{-2}$
$k=9$
Hence, the value of $k$ is 9