For the reaction ;

Question:

For the reaction ;

$\mathrm{A}(l) \rightarrow 2 \mathrm{~B}(\mathrm{~g})$

$\Delta \mathrm{U}=2.1 \mathrm{kcal}, \Delta \mathrm{S}=20 \mathrm{cal} \mathrm{} \mathrm{K}^{-1}$ at $300 \mathrm{~K}$

Hence $\Delta \mathrm{G}$ in kcal is___________

Solution:

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