Question:
For the given circuit, the power across zener diode is .......... $\mathrm{mW}$.
Solution:
$\mathrm{i}=\frac{10 \mathrm{~V}}{5 \mathrm{k} \Omega}=2 \mathrm{~mA}$
$\mathrm{I}=\frac{14 \mathrm{~V}}{1 \mathrm{k} \Omega}=14 \mathrm{~mA}$
$\therefore \mathrm{I}_{\mathrm{z}}=12 \mathrm{~mA}$
$\therefore \mathrm{P}=\mathrm{I}_{\mathrm{z}} \mathrm{V}_{\mathrm{z}}=120 \mathrm{~mW}$
Ans. 120