Question: For the function $y=x^{2}$, if $x=10$ and $\Delta x=0.1$. Find $\Delta y$.
Solution:
$y=x^{2}$
$\Delta x=0.1$
$x=10$
$\frac{d y}{d x}=2 x$
$\Rightarrow\left(\frac{d y}{d x}\right)_{x=10}=20$
$\Rightarrow \Delta y=d y=\frac{d y}{d x} d x=20 \times 0.1=2$