For the function

Question:

For the function $y=x^{2}$, if $x=10$ and $\Delta x=0.1$. Find $\Delta y$.

Solution:

$y=x^{2}$

$\Delta x=0.1$

$x=10$

$\frac{d y}{d x}=2 x$

$\Rightarrow\left(\frac{d y}{d x}\right)_{x=10}=20$

$\Rightarrow \Delta y=d y=\frac{d y}{d x} d x=20 \times 0.1=2$

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