For all rational numbers $x$ and $y,(x) \times(y)=(y) \times(x)$
True.
Let $x=2, y=3$
Then,
LHS $=2 \times 3$
$=6$
$\mathrm{RHS}=3 \times 2$
By comparing $\mathrm{LHS}$ and RHS
$6=6$
$\mathrm{LHS}=\mathrm{RHS}$
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