Question:
For a series LCR circuit with $\mathrm{R}=100 \Omega$, $\mathrm{L}=0.5 \mathrm{mH}$ and $\mathrm{C}=0.1 \mathrm{pF}$ connected across $220 \mathrm{~V}-50 \mathrm{~Hz} \mathrm{AC}$ supply, the phase angle between current and supplied voltage and the nature of the circuit is :
Correct Option: , 4
Solution:
$R=100 \Omega$
$\mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}=50 \pi \times 10^{-3}$
$X_{C}=\frac{1}{\omega C}=\frac{10^{11}}{100 \pi}$
$X_{C} \gg X_{L}$
$\&\left|X_{C}-X_{L}\right|>>R$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.