For a non zero rational number a, (a3)−2 is equal to
(a) a9
(b) a−6
(c) a−9
(d) a1
We have:
$\left(a^{3}\right)^{-2}=a^{3 \times(-2)} \quad \ldots\left(\left(a^{m}\right)^{n}=a^{m \times n}\right)$
$a^{-6 \mid}$
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