Following is the distribution of I.Q. of 100 students. Find the median I.Q.

Here, the frequency table is given in inclusive form. Transforming the given table into exclusive form and prepare the cumulative frequency table.

Here, $N=100$

So, $\frac{N}{2}=50$

Thus, the cumulative frequency just greater than 50 is 67 and the corresponding class is 94.5−104.5.

Therefore, 94.5−104.5 is the median class.

Here, $I=94.5, f=33, F=34$ and $h=9$

We know that,

Median $=l+\left\{\frac{\frac{N}{2}-F}{f}\right\} \times h$

$=94.5+\left(\frac{50-34}{33}\right) \times 10$

$=94.5+\frac{160}{33}$

$=94.5+4.85$

$=99.35$

Hence, the median is 99.35.