Question:
Find what the given equation becomes when the origin is shifted to the point (1, 1).
$x^{2}-y^{2}-2 x+2 y=0$
Solution:
Let the new origin be (h, k) = (1, 1)
Then, the transformation formula become:
x = X + 1 and y = Y + 1
Substituting the value of x and y in the given equation, we get
$x^{2}-y^{2}-2 x+2 y=0$
Thus,
$(X+1)^{2}-(Y+1)^{2}-2(X+1)+2(Y+1)=0$
$\Rightarrow\left(X^{2}+1+2 X\right)-\left(Y^{2}+1+2 Y\right)-2 X-2+2 Y+2=0$
$\Rightarrow X^{2}+1+2 X-Y^{2}-1-2 Y-2 X+2 Y=0$
$\Rightarrow X^{2}-Y^{2}=0$
Hence, the transformed equation is $X^{2}-Y^{2}=0$