Find the volume of a cuboid whose

Question:

Find the volume of a cuboid whose

(i) length = 12 cm, breadth = 8 cm, height = 6 cm

(ii) length =1.2 m, breadth = 30 cm, height = 15 cm

(iii) length = 15 cm, breadth = 2.5 dm, height = 8 cm.

Solution:

(i) In the given cuboid, we have:

length $=12 \mathrm{~cm}$, breadth $=8 \mathrm{~cm}$ and height $=6 \mathrm{~cm}$

$\therefore$ Volume of the cuboid $=$ length $\times$ breadth $\times$ height

$=12 \times 8 \times 6$

$=576 \mathrm{~cm}^{3}$

(ii) In the given cuboid, we have:

length $=1.2 \mathrm{~m}$

$=1.2 \times 100 \mathrm{~cm} \quad(1 \mathrm{~m}=100 \mathrm{~cm})$

$=120 \mathrm{~cm}$

breadth $=30 \mathrm{~cm}$

height $=15 \mathrm{~cm}$

$\therefore$ Volume of the cuboid $=$ length $\times$ breadth $\times$ height

$=120 \times 30 \times 15$

$=54000 \mathrm{~cm}^{3}$

(iii) In the given cuboid, we have:

length $=1.5 \mathrm{dm}$

$=1.5 \times 10 \quad(1 \mathrm{dm}=10 \mathrm{~cm})$

$=15 \mathrm{~cm}$

breadth $=2.5 \mathrm{dm}=2.5 \times 10 \mathrm{~cm}=25 \mathrm{~cm}$

height $=8 \mathrm{~cm}$

$\therefore$ Volume of cuboid $=$ length $\times$ breadth $\times$ height

$=15 \times 25 \times 8$

$=3000 \mathrm{~cm}^{3}$

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