Question:
Find the volume of a cube, one face of which has an area of 64 m2.
Solution:
Area of a face of cube is given by:
$A=s^{2}$, where $s=$ Side of the cube
Further, volume of a cube is given by:
$V=s^{3}$, where $s=$ Side of the cube
It is given that the area of one face of the cube is 64 m2. Therefore we have:
$s^{2}=64 \Rightarrow s=\sqrt{64}=8 \mathrm{~m}$
Now, volume is given by:
$V=s^{3}=8^{3} \Rightarrow V=8 \times 8 \times 8=512 \mathrm{~m}^{3}$
Thus, the volume of the cube is 512 m3.