Find the volume and surface area of a sphere whose radius is:
(i) 3.5 cm
(ii) 4.2 cm
(iii) 5 m
(i) Radius of the sphere = 3.5 cm
Now, volume $=\frac{4}{2} \pi r^{3}$
$=\frac{4}{3} \times \frac{22}{7} \times 3.5 \times 3.5 \times 3.5$
$=179.67 \mathrm{~cm}^{3}$
$\therefore$ Surface area $=4 \pi r^{2}$
$=4 \times \frac{22}{7} \times 3.5 \times 3.5$
$=154 \mathrm{~cm}^{2}$
(ii) Radius of the sphere=4.2 cm
Now, volume $=\frac{4}{3} \pi r^{3}$
$=\frac{4}{3} \times \frac{22}{7} \times 4.2 \times 4.2 \times 4.2$
$=310.46 \mathrm{~cm}^{3}$
$\therefore$ Surface area $=4 \pi r^{2}$
$=4 \times \frac{22}{7} \times 4.2 \times 4.2$
$=221.76 \mathrm{~cm}^{2}$
(iii) Radius of sphere=5 m
Now, volume $=\frac{4}{3} \pi r^{3}$
$=\frac{4}{3} \times \frac{22}{7} \times 5^{3}$
$=523.81 \mathrm{~cm}^{3}$
$\therefore$ Surface area $=4 \pi r^{2}$
$=4 \times \frac{22}{7} \times 5^{2}$
$=314.29 \mathrm{~cm}^{2}$