Find the value of the polynomial $5 x-4 x^{2}+3$ at <br/> <br/>(i) $x=0$ <br/> <br/>(ii) $x=-1$ <br/> <br/>(iii) $x=2$

Solution:

(i) $p(x)=5 x-4 x^{2}+3$

$p(0)=5(0)-4(0)^{2}+3$

$=3$

(ii) $p(x)=5 x-4 x^{2}+3$

$p(-1)=5(-1)-4(-1)^{2}+3$

$=-5-4(1)+3=-6$

(iii) $p(x)=5 x-4 x^{2}+3$

$p(2)=5(2)-4(2)^{2}+3$

$=10-16+3=-3$