Question:
Find the value of k for which each of the following system of equations have no solution :
$x+2 y=0$
$2 x+k y=5$
Solution:
GIVEN:
$x+2 y=0$
$2 x+k y=5$
To find: To determine for what value of k the system of equation has no solution
We know that the system of equations
$a_{1} x+b_{1} y=c_{1}$
$a_{2} x+b_{2} y=c_{2}$
For no solution
$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$
Here,
$\frac{1}{2}=\frac{2}{k} \neq \frac{0}{5}$
$\frac{1}{2}=\frac{2}{k}$
$k=4$
Hence for $k=4$ the system of equation has no solution