Find the value

Question:

Find the value

$a^{3}-1 / a^{3}-2 a+2 a$

Solution:

$=\left(a^{3}-1 / a^{3}\right)-2(a-1 / a)$

$=\left(a^{3}-(1 / a)^{3}\right)-2(a-1 / a)$

$=(a-1 / a)\left(a^{2}+a \times 1 / a+(1 / a)^{2}\right)-2(a-1 / a)$

$\left[\therefore a^{3}-b^{3}=(a-b)\left(a^{2}+a b+b^{2}\right)\right]$

$=(a-1 / a)\left(a^{2}+1+1 / a^{2}\right)-2(a-1 / a)$

$=(a-1 / a)\left(a^{2}+1+1 / a^{2}-2\right)$

$=(a-1 / a)\left(a^{2}+1 / a^{2}-1\right)$

$\therefore a^{3}-1 / a^{3}-2 a+2 a=(a-1 / a)\left(a^{2}+1 / a^{2}-1\right)$

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