Question:
Find the value
$64 a^{3}-b^{3}$
Solution:
$=(4 a)^{3}-b^{3}$
$=(4 a-b)\left((4 a)^{2}+4 a \times b+b^{2}\right)$
$\therefore\left[a^{3}-b^{3}=(a-b)\left(a^{2}+a b+b^{2}\right)\right]$
$=(4 a-b)\left(16 a^{2}+4 a b+b^{2}\right)$
$\therefore 64 a^{3}-b^{3}=(4 a-b)\left(16 a^{2}+4 a b+b^{2}\right)$
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