Question:
Find the square root of 324 by the method of repeated subtraction.
Solution:
Given number is $324 .$
Now, we subtract successive odd numbers starting from 1 as follows:
Here, $\quad 324-1=323, \quad 323-3=320$
$320-5=315, \quad 315-7=308$
$308-9=299, \quad 299-11=288$
$288-13=275,275-15=260$
$260-17=243,243-19=224$
$224-21=203,203-23=180$
$180-25=155,155-27=128$
$128-29=99, \quad 99-31=68$
$68-33=35, \quad 35-35=0$
We observe that the number 324 reduced to zero $(0)$ after subracting 18 odd numbers. So, 324 is a perfect square of 18 .
$\therefore \sqrt{324}=18$
Hence, the square root of 324 is $18 .$