Find the smallest number by which 2560

Question:

Find the smallest number by which 2560 must be multiplied so that the product is a perfect cube.

Solution:

2560

2560 can be expressed as the product of prime factors in the following manner:

$2560=2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5$

To make this a perfect square, we have to multiply it by $5 \times 5$.

Therefore, 2560 should be multiplied by 25 so that the product is a perfect cube.

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