Find the product:(3m − 4n) × (2m − 3n)
By horizontal method:
$(3 m-4 n) \times(2 m-3 n)$
$=3 m(2 m-3 n)-4 n(2 m-3 n)$
$=6 m^{2}-9 m n-8 m n+12 n^{2}$
$=6 m^{2}-17 m n+12 n^{2}$
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