Question:
Find the perimeter of the shaded region in the figure, if ABCD is a square of side 14 cm and APB and CPD are semicircles.
Solution:
Permieter of shaded region = Length of the arc APB + Length of the arc CPD + Length of AD + Length of BC
$=\frac{1}{2} \times 2 \pi r+\frac{1}{2} \times 2 \pi r+14+14$
$=2 \pi r+28$
$=2 \times \frac{22}{7} \times \frac{14}{2}+28$
$=72 \mathrm{~cm}$
Hence, the perimeter of the shaded region is 72 cm.
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