Find the number of ways in which the letters of the word ‘MACHINE’ can be arranged such that the vowels may occupy only odd positions.
To find: number of words
Condition: vowels occupy odd positions.
There are 7 letters in the word MACHINE out of which there are 3 vowels namely A C E.
There are 4 odd places in which 3 vowels are to be arranged which can be done $P(4,3)$.
The rest letters can be arranged in $4 !$ ways
Formula:
Number of permutations of $n$ distinct objects among $r$ different places, where repetition is not allowed, is
$P(n, r)=n ! /(n-r) !$
Therefore, the total number of words is
$P(4,3) 4 ! x=\frac{4 !}{(4-3) !} \times 4 !$
$=\frac{4 !}{1 !} \times 4 !=\frac{24}{1} \times 24=576$
Hence the total number of word in which vowel occupy odd positions only is 576.