Question:
Find the median of the data:
41, 43, 127, 99, 71, 92, 71, 58, 57
Solution:
Numbers are 41, 43, 127, 99, 71, 92, 71, 58, 57
Arranging the numbers in ascending order
41, 43, 57, 58, 71, 71, 92, 99, 127
n = 9 (odd)
$\therefore$ Median $=\left(\frac{\mathrm{n}+1}{2}\right)^{\text {th }}$ value
$=\left(\frac{9+1}{2}\right)^{\text {th }}$ value
$=5^{\text {th }}$ value $=71$