Find the measure of each exterior angle of a regular

Exterior angle of an $n$-sided polygon $=\left(\frac{360}{n}\right)^{\circ}$

(i) For a pentagon: $n=5$

$\therefore\left(\frac{360}{n}\right)=\left(\frac{360}{5}\right)=72^{\circ}$

(ii) For a hexagon: $n=6$

$\therefore\left(\frac{360}{n}\right)=\left(\frac{300}{6}\right)=60^{\circ}$

(iii) For a heptagon: $n=7$

$\therefore\left(\frac{360}{n}\right)=\left(\frac{360}{7}\right)=51.43^{\circ}$

(iv) For a decagon: $n=10$

$\therefore\left(\frac{360}{n}\right)=\left(\frac{360}{10}\right)=36^{\circ}$

(v) For a polygon of 15 sides: $n=15$

$\therefore\left(\frac{360}{n}\right)=\left(\frac{360}{15}\right)=24^{\circ}$