Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle.

Question:

Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle.

Solution:

x + 2x - 24 = 180°

⟹ 3x - 24 = 180°

⟹ 3x = 108° + 24

⟹ 3x = 204°

⟹ x = 204/3 = 68°

⟹ x = 68°

⟹ 2x - 24° = 2*68° - 24° = 112°

Hence, four angles are 68°, 112°, 68°, 112°.

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