Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle.
Question:
Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle.
Solution:
x + 2x - 24 = 180°
⟹ 3x - 24 = 180°
⟹ 3x = 108° + 24
⟹ 3x = 204°
⟹ x = 204/3 = 68°
⟹ x = 68°
⟹ 2x - 24° = 2*68° - 24° = 112°
Hence, four angles are 68°, 112°, 68°, 112°.