Question:
Find the least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3.
Solution:
We find the LCM of 5, 6, 4 and 3 first.
So, $\operatorname{LCM}(5,6,4,3)=2 \times 2 \times 3 \times 5=60$
Now, divide 2497 by 60, we get
To make the number completely divisible by 60, we must add a number that would make the remainder equal to 60.
Therefore, the number that must be added is 60
Hence, 23 must be added to 2497.
So, the number exactly divisible by 5, 6, 4 and 3 is 2497 + 23 = 2520