Find the inverse relation

Solution:

(i) R = {(1, 2), (1, 3), (2, 3), (3, 2), (5, 6)}

R−1 = {(2, 1), (3, 1), (3, 2), (2, 3), (6, 5)}

(ii) R = {(x, y) : x, y ∈ N, x + 2y = 8}

On solving x + 2y = 8, we get:

x = 8 -">−- 2y

On putting y = 1, we get x = 6.

On putting y = 2, we get x = 4.

On putting y = 3, we get x = 2.

∴ R = {(6, 1), (4, 2), (2, 3)}

Or,

R−1 = {(1, 6), (2, 4), (3, 2)}

(iii) R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x − 3.

x belongs to {11, 12, 13} and y belongs to {8, 10, 12}.

Also, 11 − 3 = 8 and 13 − 3 = 10

∴ R = {(11, 8), (13,10)}

Or,

R−1 = {(8, 11), (10,13)}