Find the inverse of each of the matrices, if it exists.
$\left[\begin{array}{ll}2 & 5 \\ 1 & 3\end{array}\right]$
Let $A=\left[\begin{array}{ll}2 & 5 \\ 1 & 3\end{array}\right]$
Let $A=\left[\begin{array}{ll}2 & 5 \\ 1 & 3\end{array}\right]$
We know that A = IA
$\therefore\left[\begin{array}{ll}2 & 5 \\ 1 & 3\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right] A$
$\Rightarrow\left[\begin{array}{ll}1 & \frac{5}{2} \\ 1 & 3\end{array}\right]=\left[\begin{array}{ll}\frac{1}{2} & 0 \\ 0 & 1\end{array}\right] A \quad\left(\mathrm{R}_{1} \rightarrow \frac{1}{2} \mathrm{R}_{1}\right)$
$\Rightarrow\left[\begin{array}{ll}1 & \frac{5}{2} \\ 0 & \frac{1}{2}\end{array}\right]=\left[\begin{array}{ll}\frac{1}{2} & 0 \\ -\frac{1}{2} & 1\end{array}\right] A \quad\left(\mathrm{R}_{2} \rightarrow \mathrm{R}_{2}-\mathrm{R}_{1}\right)$
$\Rightarrow\left[\begin{array}{lr}1 & 0 \\ 0 & \frac{1}{2}\end{array}\right]=\left[\begin{array}{cc}3 & -5 \\ -\frac{1}{2} & 1\end{array}\right] A \quad\left(\mathrm{R}_{1} \rightarrow \mathrm{R}_{2}-5 \mathrm{R}_{2}\right)$
$\Rightarrow\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]=\left[\begin{array}{lr}3 & -5 \\ -1 & 2\end{array}\right] A \quad\left(\mathrm{R}_{2} \rightarrow 2 \mathrm{R}_{2}\right)$
$\therefore A^{-1}=\left[\begin{array}{lr}3 & -5 \\ -1 & 2\end{array}\right]$