Find the equation of the tangent

finding the slope of the tangent by differentiating the curve

$\frac{d y}{d x}=4 x^{3}-18 x^{2}+26 x-10$

$\mathrm{m}$ (tangent) at $(0,5)=-10$

$\mathrm{~m}$ (normal) at $(0,5)=\frac{1}{10}$

equation of tangent is given by $y-y_{1}=m($ tangent $)\left(x-x_{1}\right)$

$y-5=-10 x$

$y+10 x=5$

equation of normal is given by $y-y_{1}=m($ normal $)\left(x-x_{1}\right)$

$y-5=\frac{1}{10} x$