Find the equation of the line which cuts off intercepts -3 and 5 on the x-axis

To Find: The equation of a line with intercepts -3 and 5 on the x-axis and yaxis respectively.

Given :Let $\mathrm{a}$ and $\mathrm{b}$ be the intercepts on $\mathrm{x}$-axis and $\mathrm{y}$-axis respectively.

Then, the $x$-intercept is $a=-3$

$y$-intercept is $b=5$

Formula used:

we know that intercept form of a line is given by:

$\frac{x}{a}+\frac{y}{b}=1$

$\frac{x}{-3}+\frac{y}{5}=1$

$5 x-3 y=-15$

$5 x-3 y+15=0$

Hence 5x - 3y + 15 = 0 is the required equation of the given line.